A can do a piece of work in 20 days and B in 30 days. They work together for some time and then B leaves. If A completes the remaining work in 5 days, for how many days did they work together? MCQ with Answer and Explanation
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Question #1
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If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same work?
Correct Answer: Option B
Explanation:
3 Men = 6 Women => 1 Man = 2 Women. 12 Men + 8 Women = 12(2 Women) + 8 Women = 32 Women. If 6 women do it in 16 days, then 32 women do it in (6 * 16) / 32 = 3 days.
3 Men = 6 Women => 1 Man = 2 Women. 12 Men + 8 Women = 12(2 Women) + 8 Women = 32 Women. If 6 women do it in 16 days, then 32 women do it in (6 * 16) / 32 = 3 days.
This question belongs to:
Maths
Time and Work
Question #2
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16 men can complete a work in 20 days. If 20 men work at the same rate, in how many days will the work be completed?
Correct Answer: Option C
Explanation:
Total work = 16 × 20 = 320 man-days. Required days = 320/20 = 16.0 days.
Total work = 16 × 20 = 320 man-days. Required days = 320/20 = 16.0 days.
This question belongs to:
Maths
Time and Work
Question #3
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A can complete a work in 11 days and B can complete the same work in 31 days. If they work together, in how many days will the work be completed?
Correct Answer: Option C
Explanation:
Combined rate = 1/11 + 1/31. Time = 1 ÷ combined rate = 8.12 days.
Combined rate = 1/11 + 1/31. Time = 1 ÷ combined rate = 8.12 days.
This question belongs to:
Maths
Time and Work
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