A cell of emf 2 V and internal resistance 0.5 Ω is connected to a 3.5 Ω resistor. Terminal voltage is MCQ with Answer and Explanation

A cell of emf 2 V and internal resistance 0.5 Ω is connected to a 3.5 Ω resistor. Terminal voltage is
A. 0.25 V
B. 2 V
C. 1.75 V
D. 1.5 V
Answer: Option C
Solution (By JKExamLibrary)
I = E/(R+r) = 2/(3.5+0.5) = 2/4 = 0.5 A. Terminal V = IR = 0.5×3.5 = 1.75 V. Or E - Ir = 2 - 0.5×0.5 = 1.75 V.

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