A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet? MCQ with Answer and Explanation
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
A. 12:00 PM
B. 11:00 AM
C. 10:00 AM
D. 1:00 PM
Answer: Option B
Solution (By JKExamLibrary)
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.
Explanation:
Speed of second train = 400 / 4 = 100 km/h. Ratio is 7:8, so 8 parts = 100 km/h. 1 part = 12.5 km/h. First train speed = 7 parts = 7 * 12.5 = 87.5 km/h.
Excluding stoppages, a transit truck travels at 75 km/h and including stoppages it travels at 62.5 km/h. How many minutes does the truck stop per hour?
The speed index tracking profile of an express locomotive is exactly 20% higher than a commercial car. Both take off from terminal M together and reach terminal N, 120 km away, at the same instant. On the corridor route, the train logs a total stall of 10 minutes at intermediate stations. Find the car speed.
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