A number is divided into two parts. 40% of the first part exceeds 30% of the second part by 20, and 50% of the second part exceeds 25% of the first part by 25. Find the number. MCQ with Answer and Explanation

A number is divided into two parts. 40% of the first part exceeds 30% of the second part by 20, and 50% of the second part exceeds 25% of the first part by 25. Find the number.
A. 300
B. 260
C. 240
D. 200
Answer: Option B
Solution (By JKExamLibrary)
Let parts x, y. 0.4x - 0.3y = 20 → 4x - 3y = 200. 0.5y - 0.25x = 25 → 20y - 10x = 1000 → 2y - x = 100. Solve: x = 2y - 100. Substitute: 4(2y-100)-3y=200 → 8y-400-3y=200 → 5y=600 → y=120, x=140, sum=260.

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Practice More Percentage Questions

Question #1
A's marks 30% more than B, B's 20% less than C. A=156, C's marks:
A. 140
B. 150
C. 160
D. 130

Correct Answer: Option B


Explanation:
A=1.3B, B=0.8C → A=1.04C → C=156/1.04=150.

This question belongs to: Maths Percentage
Question #2
A number increased by 25% then by 20% becomes 180. Original number:
A. 100
B. 110
C. 130
D. 120

Correct Answer: Option D


Explanation:
x × 1.25 × 1.2 = 1.5x = 180 → x = 120.

This question belongs to: Maths Percentage
Question #3
The ratio of boys to girls in a school is 3:2. If 20% of boys and 25% of girls are adults, what percentage of the total students are non-adults?
A. 70%
B. 78%
C. 80%
D. 75%

Correct Answer: Option B


Explanation:
Let boys = 60, girls = 40. Total = 100. Adult boys = 20% of 60 = 12. Adult girls = 25% of 40 = 10. Total adults = 22. Non-adults = 100 - 22 = 78. Percentage = 78%.

This question belongs to: Maths Percentage