A person of mass 60 kg stands on a weighing scale in an elevator accelerating upward at 2 m/s² (g=10). The reading is MCQ with Answer and Explanation

A person of mass 60 kg stands on a weighing scale in an elevator accelerating upward at 2 m/s² (g=10). The reading is

A. 120 kg

B. 72 kg

C. 48 kg

D. 60 kg

Answer: Option B

Solution (By JKExamLibrary)

Apparent weight = m(g+a) = 60×(10+2) = 720 N, which corresponds to 72 kg mass on scale (if scale calibrated in kg under g=10). Reading 72 kg. Downward acceleration would reduce.

This question belongs to: Science Physics

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A wire of resistance 10 Ω is stretched to double its length. Its new resistance is

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C. 20 Ω

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Resistance R = ρL/A. Volume constant: A ∝ 1/L. Stretching length to 2L reduces area to A/2. New R' = ρ(2L)/(A/2) = 4ρL/A = 4R = 40 Ω. Resistance proportional to (length)² when volume constant.

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