A person walks from his villa to a local station at 4 km/h and arrives 10 minutes late. If he routes at 5 km/h, he arrives 2 minutes early. Find the distance. MCQ with Answer and Explanation
A person walks from his villa to a local station at 4 km/h and arrives 10 minutes late. If he routes at 5 km/h, he arrives 2 minutes early. Find the distance.
A. 4.5 km
B. 4.0 km
C. 5.0 km
D. 3.5 km
Answer: Option B
Solution (By JKExamLibrary)
Time difference = 10 - (-2) = 12 minutes = 12/60 = 0.2 hours. Let distance be d. d/4 - d/5 = 0.2 => d/20 = 0.2 => d = 4 km.
Explanation:
New speed = 5/6 of usual speed => New time = 6/5 of usual time. Difference = 1/5 of usual time = 15 minutes. Typical baseline time parameter = 15 * 5 = 75 minutes.
Explanation:
The second man covers 10 meters in 2 seconds, so his speed = 10 / 2 = 5 m/s. Total time taken by second man to complete 100m = 100 / 5 = 20 seconds. Since the winner beats him by 2 seconds, winner's time = 20 - 2 = 18 seconds.
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