A screw gauge has a pitch of 1 mm and 100 divisions on its circular scale. The least count of this instrument is: MCQ with Answer and Explanation

A screw gauge has a pitch of 1 mm and 100 divisions on its circular scale. The least count of this instrument is:
A. 0.001 mm
B. 0.1 mm
C. 0.0001 mm
D. 0.01 mm
Answer: Option D
Solution (By JKExamLibrary)
Least count of screw gauge = Pitch / Number of circular scale divisions. Given pitch = 1 mm, divisions = 100, so LC = 1 mm / 100 = 0.01 mm. This represents the smallest measurement the instrument can accurately detect. Screw gauges measure small dimensions like wire diameter with high precision. Memory tip: Least count formula is universal for vernier and screw instruments: value per division on main scale divided by total circular divisions. This concept is frequently tested in practical physics sections of competitive exams.

This question belongs to: Science Physics

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