A step-down transformer has turns ratio 10:1. Input voltage 220 V, output voltage is MCQ with Answer and Explanation
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Question #1
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The buoyant force on an object immersed in a fluid depends on
Correct Answer: Option D
Explanation:
Buoyant force = weight of displaced fluid = ρ_fluid × V_displaced × g. Independent of depth (if fluid incompressible) and object's density, though object density determines if it floats. Shape affects volume displaced when floating.
Buoyant force = weight of displaced fluid = ρ_fluid × V_displaced × g. Independent of depth (if fluid incompressible) and object's density, though object density determines if it floats. Shape affects volume displaced when floating.
Question #2
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Magnetic field lines inside a bar magnet go from
Question #3
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A body floats in a liquid with one-third of its volume above the surface. The density of the body relative to the liquid is:
Correct Answer: Option D
Explanation:
By Archimedes' principle, weight of body = weight of displaced liquid. Let V be total volume, ρ_b body density, ρ_l liquid density. Volume submerged = (2/3)V. Thus ρ_b·V·g = ρ_l·(2V/3)·g ⇒ ρ_b/ρ_l = 2/3. Fraction submerged equals density ratio. Memory tip: 'Fraction submerged = ρ_object / ρ_fluid'. This direct application of floatation condition is common in competitive exams. Always identify submerged fraction correctly: here 'one-third above' means two-thirds submerged. Such problems test conceptual clarity in buoyancy applications.
By Archimedes' principle, weight of body = weight of displaced liquid. Let V be total volume, ρ_b body density, ρ_l liquid density. Volume submerged = (2/3)V. Thus ρ_b·V·g = ρ_l·(2V/3)·g ⇒ ρ_b/ρ_l = 2/3. Fraction submerged equals density ratio. Memory tip: 'Fraction submerged = ρ_object / ρ_fluid'. This direct application of floatation condition is common in competitive exams. Always identify submerged fraction correctly: here 'one-third above' means two-thirds submerged. Such problems test conceptual clarity in buoyancy applications.
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