A stone is thrown vertically upward with velocity 49 m/s. The time after which it returns to thrower is (g=9.8) MCQ with Answer and Explanation

A stone is thrown vertically upward with velocity 49 m/s. The time after which it returns to thrower is (g=9.8)
A. 5 s
B. 15 s
C. 2.5 s
D. 10 s
Answer: Option D
Solution (By JKExamLibrary)
Time of flight T = 2u/g = 2×49/9.8 = 98/9.8 = 10 s. Up and down symmetric. Max height = u²/(2g) = 122.5 m.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
Which of the following is the dimensional formula of impulse?
A. [MLT⁻¹]
B. [ML²T⁻¹]
C. [M⁰LT⁻¹]
D. [MLT⁻²]

Correct Answer: Option A


Explanation:
Impulse = Force × time = change in momentum. Momentum = mass × velocity, dimensions [M][LT⁻¹] = [MLT⁻¹]. Force dimensions [MLT⁻²], multiplied by time gives [MLT⁻¹]. Same as momentum.

This question belongs to: Science Physics
Question #2
Two bodies of masses m and 2m are dropped from a height. Neglecting air resistance, which hits first?
A. m
B. Depends on height
C. 2m
D. Both same

Correct Answer: Option D


Explanation:
Acceleration g same for all masses in vacuum.

This question belongs to: Science Physics
Question #3
The ratio of SI to CGS unit of force is
A. 10⁷
B. 10²
C. 10³
D. 10⁵

Correct Answer: Option D


Explanation:
SI unit Newton (kg m/s²), CGS unit dyne (g cm/s²). 1 N = 10⁵ dyne. Conversion: 1 kg = 10³ g, 1 m = 100 cm, so 1 N = 10³ × 10² = 10⁵ dyne. Ratio N/dyne = 10⁵.

This question belongs to: Science Physics