Baking powder is a mixture of baking soda and: MCQ with Answer and Explanation

Baking powder is a mixture of baking soda and:
A. A mild edible acid like tartaric acid
B. Sodium chloride
C. Calcium carbonate
D. Ammonium sulfate
Answer: Option A
Solution (By JKExamLibrary)
Baking powder contains sodium bicarbonate (NaHCO₃) and a weak solid acid such as tartaric acid or cream of tartar (potassium hydrogen tartrate). When moistened, they react to produce CO₂, making dough rise. Baking soda alone requires an acidic ingredient (yogurt, lemon). The acid in baking powder ensures reliable leavening. Sodium chloride and calcium carbonate do not serve this purpose.

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Practice More chemistry Questions

Question #1
Enzymes are biological catalysts. Which statement about them is correct?
A. They work optimally at very high temperatures.
B. They are consumed during the reaction.
C. They are highly specific in their action.
D. They are inorganic compounds.

Correct Answer: Option C


Explanation:
Enzymes are proteins that act as catalysts, exhibiting high specificity for substrates (lock-and-key model). They are not consumed, denature at high temperatures, and are organic. Examples: amylase for starch, pepsin for proteins.

This question belongs to: Science chemistry
Question #2
Which of the following has a triple bond?
A. Ethene
B. Benzene
C. Ethane
D. Ethyne

Correct Answer: Option D


Explanation:
Ethyne (C₂H₂) has a carbon-carbon triple bond (HC≡CH). Ethene has double; ethane single; benzene has delocalized pi bonds.

This question belongs to: Science chemistry
Question #3
The bond in CO is actually a triple bond with a coordinate covalent bond. The total number of electrons shared between C and O in CO is:
A. 8
B. 6
C. 2
D. 4

Correct Answer: Option B


Explanation:
CO has a triple bond: one sigma and two pi bonds, with a coordinate covalent character where oxygen donates a lone pair to carbon, forming a bond similar to triple bond. Total shared electrons = 6 (three pairs). Lewis structure shows :C≡O: with formal charges. The bond order is 3. It is isoelectronic with N₂ and CN⁻.

This question belongs to: Science chemistry