Carnot efficiency η = 1 - T₂/T₁. If T₁=600K, T₂=300K, η is: MCQ with Answer and Explanation

Carnot efficiency η = 1 - T₂/T₁. If T₁=600K, T₂=300K, η is:
A. 100%
B. 75%
C. 25%
D. 50%
Answer: Option D
Solution (By JKExamLibrary)
η = 1 - 300/600 = 1 - 0.5 = 0.5 = 50%. Maximum possible efficiency for given temperatures. Memory aid: 'η_Carnot = 1 - T_cold/T_hot; always < 100%'. Thermodynamics calculation frequently tested in competitive exams.

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