Critical angle for glass (n=1.5) to air: MCQ with Answer and Explanation

Critical angle for glass (n=1.5) to air:
A. 60°
B. 30°
C. 90°
D. 42°
Answer: Option D
Solution (By JKExamLibrary)
sinθ_c = n₂/n₁ = 1/1.5 = 2/3 ⇒ θ_c = sin⁻¹(0.667) ≈ 42°. Total internal reflection condition. Memory tip: 'θ_c = sin⁻¹(1/n) for denser to air'. Optics calculation frequently tested in competitive exams with standard refractive indices.

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A ray of light traveling from water (denser) into air (rarer) grazes the interface separating the two media. The angle of incidence in the water is called the:
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