Fleming's left hand rule gives direction of MCQ with Answer and Explanation
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Question #1
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A body is thrown vertically upward with speed 40 m/s. Distance travelled in last second of ascent (g=10)
Correct Answer: Option D
Explanation:
Time of ascent = u/g = 4 s. Distance in last second (4th) = ½g(1)²? Actually, during last second of upward journey, velocity becomes zero. Distance = ½g(1)² = 5 m. Formula: s = u - g/2 (2n-1) with n=4? Let's compute: s_nth = u - (g/2)(2n-1). For n=4 (4th second), s = 40 - 5×7 = 40 - 35 = 5 m. Yes.
Time of ascent = u/g = 4 s. Distance in last second (4th) = ½g(1)²? Actually, during last second of upward journey, velocity becomes zero. Distance = ½g(1)² = 5 m. Formula: s = u - g/2 (2n-1) with n=4? Let's compute: s_nth = u - (g/2)(2n-1). For n=4 (4th second), s = 40 - 5×7 = 40 - 35 = 5 m. Yes.
Question #2
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The Q factor of a resonant LCR circuit is measure of
Question #3
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Polarization impossible in:
Correct Answer: Option D
Explanation:
Polarization requires transverse waves. Sound in air is longitudinal (oscillations ∥ propagation) ⇒ cannot be polarized. EM waves (light, radio, X-rays) are transverse ⇒ can be polarized. Memory tip: 'Polarization ⇒ transverse only; sound = longitudinal ⇒ no polarization'. Wave property frequently tested in competitive exams.
Polarization requires transverse waves. Sound in air is longitudinal (oscillations ∥ propagation) ⇒ cannot be polarized. EM waves (light, radio, X-rays) are transverse ⇒ can be polarized. Memory tip: 'Polarization ⇒ transverse only; sound = longitudinal ⇒ no polarization'. Wave property frequently tested in competitive exams.
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