If 6 men and 8 boys can do a piece of work in 10 days, then 3 men and 4 boys will do the same work in: MCQ with Answer and Explanation
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Question #1
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A can complete a work in 17 days and B can complete the same work in 17 days. If they work together, in how many days will the work be completed?
Correct Answer: Option C
Explanation:
Combined rate = 1/17 + 1/17. Time = 1 ÷ combined rate = 8.5 days.
Combined rate = 1/17 + 1/17. Time = 1 ÷ combined rate = 8.5 days.
This question belongs to:
Maths
Time and Work
Question #2
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23 men can complete a work in 30 days. If 28 men work at the same rate, the work will be completed in:
Correct Answer: Option D
Explanation:
Total work = 690 man-days. Time = 690/28 = 24.64 days.
Total work = 690 man-days. Time = 690/28 = 24.64 days.
This question belongs to:
Maths
Time and Work
Question #3
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A, B and C can do a piece of work in 20, 30 and 60 days respectively. If A works everyday and is assisted by B and C together on every third day, then in how many days will the work be completed?
Correct Answer: Option D
Explanation:
Total work = LCM(20, 30, 60) = 60 units. Efficiency of A = 3, B = 2, C = 1. Day 1: A works = 3 units. Day 2: A works = 3 units. Day 3: A+B+C work = 3 + 2 + 1 = 6 units. Work done in 3 days = 3 + 3 + 6 = 12 units. Number of 3-day cycles to complete 60 units = 60 / 12 = 5 cycles. Total days = 5 * 3 = 15 days.
Total work = LCM(20, 30, 60) = 60 units. Efficiency of A = 3, B = 2, C = 1. Day 1: A works = 3 units. Day 2: A works = 3 units. Day 3: A+B+C work = 3 + 2 + 1 = 6 units. Work done in 3 days = 3 + 3 + 6 = 12 units. Number of 3-day cycles to complete 60 units = 60 / 12 = 5 cycles. Total days = 5 * 3 = 15 days.
This question belongs to:
Maths
Time and Work
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