If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be: MCQ with Answer and Explanation
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
A. 7 days
B. 4 days
C. 5 days
D. 6 days
Answer: Option B
Solution (By JKExamLibrary)
Total work = 10 * (6M + 8B) = 2 * (26M + 48B) => 60M + 80B = 52M + 96B => 8M = 16B => 1M = 2B. Total work in terms of boys = 10 * (6*2B + 8B) = 10 * 20B = 200 boy-days. Efficiency of 15 men and 20 boys = 15*2B + 20B = 50B. Time taken = 200 / 50 = 4 days.
Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 6 days, work done = 6 * 7 = 42 units. Remaining work = 60 - 42 = 18 units. Time taken by A to complete remaining work = 18 / 4 = 4.5 days.
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