If the half-life of a radioactive substance is 10 days, what fraction of the original substance will remain after 30 days? MCQ with Answer and Explanation

If the half-life of a radioactive substance is 10 days, what fraction of the original substance will remain after 30 days?
A. 1/16
B. 1/2
C. 1/4
D. 1/8
Answer: Option D
Solution (By JKExamLibrary)
The number of half-lives elapsed is 30 days / 10 days = 3. The fraction remaining is (1/2)ⁿ, where n is the number of half-lives. So, (1/2)³ = 1/8. After 10 days: 1/2; after 20 days: 1/4; after 30 days: 1/8 of the original amount remains.

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