J. J. Thomson is credited with the discovery of: MCQ with Answer and Explanation
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Question #1
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A piece of ice floats in water with 1/10 of its volume above water. The density of ice is
Question #2
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A body is thrown vertically upwards. At the highest point of its trajectory:
Correct Answer: Option A
Explanation:
At maximum height, vertical velocity becomes zero momentarily. However, acceleration due to gravity (g) acts downward throughout the motion, including at the peak. Thus acceleration is g ≈ 9.8 m/s² downward, not zero. Memory tip: 'Peak of projectile: v=0, a=g downward'. This conceptual question tests understanding of motion under gravity, frequently appearing in competitive exams. Always distinguish velocity (which changes) from acceleration (constant in free fall near Earth). Misconception that acceleration is zero at peak is a common trap.
At maximum height, vertical velocity becomes zero momentarily. However, acceleration due to gravity (g) acts downward throughout the motion, including at the peak. Thus acceleration is g ≈ 9.8 m/s² downward, not zero. Memory tip: 'Peak of projectile: v=0, a=g downward'. This conceptual question tests understanding of motion under gravity, frequently appearing in competitive exams. Always distinguish velocity (which changes) from acceleration (constant in free fall near Earth). Misconception that acceleration is zero at peak is a common trap.
Question #3
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TIR requires light travel from:
Correct Answer: Option B
Explanation:
TIR: denser→rarer medium AND incidence angle > critical angle. Glass to air satisfies first condition; angle must exceed θ_c. Memory aid: 'TIR: n₁>n₂ AND i>θ_c; direction matters'. Optics condition frequently tested in competitive exams.
TIR: denser→rarer medium AND incidence angle > critical angle. Glass to air satisfies first condition; angle must exceed θ_c. Memory aid: 'TIR: n₁>n₂ AND i>θ_c; direction matters'. Optics condition frequently tested in competitive exams.
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