Percentage MCQs
Practice Percentage MCQs with answers and detailed explanations. Learn percentage calculations, increase and decrease percentages, profit and loss percentages, discounts, percentage change and exam-oriented quantitative aptitude questions designed for SSC, Railway, Banking, UPSC, JKSSB, Police, Teaching and other competitive exams.
Question #31
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A number is increased by 10% and then decreased by 10%. What is the net change?
Correct Answer: Option C
Explanation:
Net change = x^2 / 100 % decrease. 10^2 / 100 = 1% decrease.
Net change = x^2 / 100 % decrease. 10^2 / 100 = 1% decrease.
This question belongs to:
Maths
Percentage
Question #32
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A number is increased by 20% and then decreased by 20%. What is the net change?
Correct Answer: Option D
Explanation:
Net change = x^2 / 100 % decrease. 20^2 / 100 = 400 / 100 = 4% decrease.
Net change = x^2 / 100 % decrease. 20^2 / 100 = 400 / 100 = 4% decrease.
This question belongs to:
Maths
Percentage
Question #33
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Find the single equivalent discount for successive discounts of 10% and 20%.
Correct Answer: Option B
Explanation:
Equivalent discount = a + b - (ab / 100). 10 + 20 - (10 * 20 / 100) = 30 - 2 = 28%.
Equivalent discount = a + b - (ab / 100). 10 + 20 - (10 * 20 / 100) = 30 - 2 = 28%.
This question belongs to:
Maths
Percentage
Question #34
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Find the single equivalent discount for successive discounts of 20% and 20%.
Correct Answer: Option A
Explanation:
Equivalent discount = 20 + 20 - (20 * 20 / 100) = 40 - 4 = 36%.
Equivalent discount = 20 + 20 - (20 * 20 / 100) = 40 - 4 = 36%.
This question belongs to:
Maths
Percentage
Question #35
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The price of an item increases by 25% and then decreases by 20%. What is the net percentage change?
Correct Answer: Option C
Explanation:
Net change = 25 - 20 + ((25 * -20) / 100) = 5 - 5 = 0%.
Net change = 25 - 20 + ((25 * -20) / 100) = 5 - 5 = 0%.
This question belongs to:
Maths
Percentage
Question #36
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A town's population increases by 10% in the first year and 20% in the second year. What is the net percentage increase?
Correct Answer: Option B
Explanation:
Net change = 10 + 20 + ((10 * 20) / 100) = 30 + 2 = 32%.
Net change = 10 + 20 + ((10 * 20) / 100) = 30 + 2 = 32%.
This question belongs to:
Maths
Percentage
Question #37
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A salary is increased by 30% and then decreased by 30%. What is the net change?
Correct Answer: Option A
Explanation:
Net change = x^2 / 100 % decrease. 30^2 / 100 = 900 / 100 = 9% decrease.
Net change = x^2 / 100 % decrease. 30^2 / 100 = 900 / 100 = 9% decrease.
This question belongs to:
Maths
Percentage
Question #38
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Find the single equivalent discount for successive discounts of 50% and 50%.
Correct Answer: Option A
Explanation:
Equivalent discount = 50 + 50 - (50 * 50 / 100) = 100 - 25 = 75%.
Equivalent discount = 50 + 50 - (50 * 50 / 100) = 100 - 25 = 75%.
This question belongs to:
Maths
Percentage
Question #39
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If the price of sugar increases by 25%, by what percentage must consumption be reduced so that expenditure remains the same?
Correct Answer: Option B
Explanation:
Required reduction = (R / (100 + R)) * 100. (25 / 125) * 100 = 20%.
Required reduction = (R / (100 + R)) * 100. (25 / 125) * 100 = 20%.
This question belongs to:
Maths
Percentage
Question #40
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If the price of tea increases by 20%, by what percentage must consumption be reduced to keep expenditure constant?
Correct Answer: Option A
Explanation:
Required reduction = (20 / 120) * 100 = 100 / 6 = 16.67%.
Required reduction = (20 / 120) * 100 = 100 / 6 = 16.67%.
This question belongs to:
Maths
Percentage
