Myopia (nearsightedness) is corrected by using MCQ with Answer and Explanation

Myopia (nearsightedness) is corrected by using
A. Concave lens
B. Bifocal lens
C. Convex lens
D. Cylindrical lens
Answer: Option A
Solution (By JKExamLibrary)
Myopic eye focuses image in front of retina. A diverging (concave) lens spreads light so image falls on retina. Hypermetropia (farsightedness) corrected by convex lens. Bifocals for presbyopia. Cylindrical for astigmatism.

This question belongs to: Science Physics

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Practice More Physics Questions

Question #1 Report Error
A step-up transformer increases
A. Voltage
B. Current
C. Power
D. Energy

Correct Answer: Option A


Explanation:
Step-up transformer increases voltage and decreases current proportionally (P = V×I constant ideal). Power constant (ignoring losses). Used in power transmission to reduce I²R losses. Step-down decreases voltage.

This question belongs to: Science Physics
Question #2 Report Error
A piece of ice floats in water with 1/10 of its volume above water. The density of ice is
A. 1.0 g/cm³
B. 0.5 g/cm³
C. 0.8 g/cm³
D. 0.9 g/cm³

Correct Answer: Option D


Explanation:
Fraction of volume submerged = ρ_ice / ρ_water. If 1/10 above, 9/10 submerged. So ρ_ice/ρ_water = 9/10 => ρ_ice = 0.9 g/cm³. Density of ice is 0.9 g/cm³.

This question belongs to: Science Physics
Question #3 Report Error
A constant force acting on a body of mass 5 kg changes its speed from 2 m/s to 8 m/s in 10 s. The magnitude of force is
A. 1 N
B. 5 N
C. 0.5 N
D. 3 N

Correct Answer: Option D


Explanation:
Acceleration a = (v-u)/t = (8-2)/10 = 0.6 m/s². Force F = m×a = 5 × 0.6 = 3 N. Alternatively, impulse = change in momentum = 5×(8-2) = 30 kg m/s, time = 10 s, so average force = 30/10 = 3 N. Always check direction, but magnitude is 3 N.

This question belongs to: Science Physics