Ratio of present ages of A and B is 7:5. After 7 years, the ratio becomes 10:8. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 7:5. After 7 years, the ratio becomes 10:8. Present age of A is?

A. 126 years

B. 252 years

C. 131 years

D. 123 years

Answer: Option A

Let ages 7k and 5k. Then (7k + 7)/(5k + 7) = 10/8. Solving gives k ≈ 18, age of A = 7*18 = 126.

This question belongs to: Maths Ratio and Proportion

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Question #1 Report Error

Two numbers are in ratio 7:4. Their difference is 73. What is their sum?

A. 297

B. 636

C. 734

D. 594

Correct Answer: Option D

Explanation:
Numbers 7k, 4k. Difference |7-4|k = 73 ⇒ k = 24. Sum = (7+4)k ≈ 594.

This question belongs to: Maths Ratio and Proportion

Question #2 Report Error

Two numbers are in the ratio 7:15 and their sum is 454. Find the numbers.

A. 170 and 281

B. 126 and 320

C. 140 and 300

D. 280 and 600

Correct Answer: Option C

Explanation:
Numbers = 7k and 15k. 7k + 15k = 454 ⇒ k = 20. Thus, numbers are 140 and 300.

This question belongs to: Maths Ratio and Proportion

Question #3 Report Error

Two numbers are in the ratio 14:12 and their sum is 772. Find the numbers.

A. 389 and 367

B. 406 and 348

C. 812 and 696

D. 421 and 329

Correct Answer: Option B

Explanation:
Numbers = 14k and 12k. 14k + 12k = 772 ⇒ k = 29. Thus, numbers are 406 and 348.

This question belongs to: Maths Ratio and Proportion