Ratio of present ages of A and B is 7:6. After 11 years, the ratio becomes 9:9. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 7:6. After 11 years, the ratio becomes 9:9. Present age of A is?
A. 103 years
B. 196 years
C. 98 years
D. 95 years
Answer: Option C
Solution (By JKExamLibrary)
Let ages 7k and 6k. Then (7k + 11)/(6k + 11) = 9/9. Solving gives k ≈ 14, age of A = 7*14 = 98.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
If a:b = 5:5 and b:c = 5:4, then a:b:c = ?
A. 5:5:4
B. 10:10:8
C. 5:6:4
D. 4:5:5

Correct Answer: Option A


Explanation:
Combine ratios: a:b = 5:5, b:c = 5:4 ⇒ a:b:c = 5:5:4.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
Two numbers are in ratio 8:5. Their difference is 125. What is their sum?
A. 201
B. 519
C. 403
D. 445

Correct Answer: Option C


Explanation:
Numbers 8k, 5k. Difference |8-5|k = 125 ⇒ k = 41. Sum = (8+5)k ≈ 403.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
Two numbers are in the ratio 13:4 and their sum is 771. Find the numbers.
A. 585 and 180
B. 1170 and 360
C. 578 and 197
D. 609 and 170

Correct Answer: Option A


Explanation:
Numbers = 13k and 4k. 13k + 4k = 771 ⇒ k = 45. Thus, numbers are 585 and 180.

This question belongs to: Maths Ratio and Proportion