Ratio of present ages of A and B is 7:7. After 10 years, the ratio becomes 10:8. Present age of A is? MCQ with Answer and Explanation

Ratio of present ages of A and B is 7:7. After 10 years, the ratio becomes 10:8. Present age of A is?

A. 308 years

B. 154 years

C. 159 years

D. 150 years

Answer: Option B

Let ages 7k and 7k. Then (7k + 10)/(7k + 10) = 10/8. Solving gives k ≈ 22, age of A = 7*22 = 154.

This question belongs to: Maths Ratio and Proportion

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Question #1 Report Error

Two numbers are in ratio 7:5. Their difference is 102. What is their sum?

A. 252

B. 647

C. 504

D. 546

Correct Answer: Option C

Explanation:
Numbers 7k, 5k. Difference |7-5|k = 102 ⇒ k = 51. Sum = (7+5)k ≈ 504.

This question belongs to: Maths Ratio and Proportion

Question #2 Report Error

Ratio of present ages of A and B is 6:6. After 12 years, the ratio becomes 8:7. Present age of A is?

A. 72 years

B. 64 years

C. 77 years

D. 144 years

Correct Answer: Option A

Explanation:
Let ages 6k and 6k. Then (6k + 12)/(6k + 12) = 8/7. Solving gives k ≈ 12, age of A = 6*12 = 72.

This question belongs to: Maths Ratio and Proportion

Question #3 Report Error

Milk and water are in ratio 7:7 in a 233 L mixture. Quantity of milk?

A. 232 L

B. 117 L

C. 138 L

D. 116 L

Correct Answer: Option D

Explanation:
Total parts = 14. Milk = [7 / (7+7)] × 233 = 116 L.

This question belongs to: Maths Ratio and Proportion