Rohan walks 9 km east, then turns right and walks 12 km. What is the shortest distance from his starting point? MCQ with Answer and Explanation

Explanation:
This forms a right triangle where the final hypotenuse distance is 50m, and one leg (the horizontal walk) is 30m. The vertical walk (y) is found using Pythagoras: y² + 30² = 50² -> y² + 900 = 2500 -> y² = 1600 -> y = 40m.

Explanation:
Faces South. 45° CW turn = South-West. Then a 90° CCW turn shifts him from South-West directly to South-East.

Explanation:
Net east = -4+12=8 km, north=3 km. Distance = √(8²+3²)=√(64+9)=√73 ≈ 8.54. Not 13. I'll change: 5 km west, 12 km north, 10 km east -> net east 5, north 12 => √(5²+12²)=13. So question: 5 km west, 12 km north, 10 km east. Shortest distance 13 km. I'll adjust: A man walks 5 km west, then 12 km north, then 10 km east. Shortest distance? 13 km. So I'll replace.