Simple pendulum period T = 2π√(l/g). If length quadrupled, T becomes: MCQ with Answer and Explanation

Simple pendulum period T = 2π√(l/g). If length quadrupled, T becomes:
A. Double
B. Four times
C. Half
D. Same
Answer: Option A
Solution (By JKExamLibrary)
T ∝ √l. If l' = 4l, T' = √4 × T = 2T. Period doubles when length quadruples. Memory aid: 'Pendulum: T ∝ √l; 4× length ⇒ 2× period'. Proportional reasoning frequently tested in competitive oscillations sections.

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Correct Answer: Option C


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