The angle of minimum deviation for a prism depends on: MCQ with Answer and Explanation

The angle of minimum deviation for a prism depends on:
A. Wavelength of light only
B. Refractive index only
C. Angle of prism only
D. Both angle of prism and refractive index
Answer: Option D
Solution (By JKExamLibrary)
Minimum deviation δ_m for a prism: n = sin[(A + δ_m)/2] / sin(A/2), where A is prism angle, n refractive index. Thus δ_m depends on both A and n. Since n varies with wavelength (dispersion), δ_m also depends on wavelength, but the primary dependencies are A and n. Memory tip: 'δ_m increases with A and n; used to measure n'. This optics formula application is frequently tested in competitive exams. Always recall that minimum deviation occurs when ray passes symmetrically through prism, a key condition for derivation.

This question belongs to: Science Physics

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1 Report Error
A body of mass 2 kg has momentum 10 kg m/s. Its kinetic energy is
A. 5 J
B. 25 J
C. 50 J
D. 20 J

Correct Answer: Option B


Explanation:
Kinetic energy K = p²/(2m) = (10)²/(2×2) = 100/4 = 25 J. Also, velocity v = p/m = 5 m/s, K = ½×2×5² = 25 J. Formula p²/(2m) is useful for quick computation. Always ensure units: kg, m/s, J.

This question belongs to: Science Physics
Question #2 Report Error
Which is the most penetrating radiation?
A. Alpha
B. Gamma
C. X-rays
D. Beta

Correct Answer: Option B


Explanation:
Gamma rays highest penetration, alpha least.

This question belongs to: Science Physics
Question #3 Report Error
A satellite in a circular orbit of radius R has period T. For radius 4R, period is
A. 4T
B. 2T
C. T/2
D. 8T

Correct Answer: Option D


Explanation:
Kepler's 3rd law: T² ∝ R³ => T' = T (4)^(3/2) = T×8 = 8T.

This question belongs to: Science Physics