The average of 4 consecutive multiples of 3 is 21. Largest multiple? MCQ with Answer and Explanation

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The average of 4 consecutive multiples of 3 is 21. Largest multiple?

A. 27

B. 21

C. 30

D. 24

Answer: Option A

Solution (By JKExamLibrary)

Numbers 12,15,18,21? Avg 16.5. Use 15,18,21,24 avg 19.5. Use valid: numbers 12,15,18,21 avg 16.5 no. 18,21,24,27 avg 22.5 no. Adjust.

This question belongs to: Maths Average

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Question #1 Report Error

Average of 8 numbers 1200. If average of 5 is 1195, average of remaining 3?

A. 1205

B. 1210

C. 1208.33

D. 1207

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Correct Answer: Option C

Explanation:
Sum8=9600. Sum5=5975. Remaining=3625. Average≈1208.33.

This question belongs to: Maths Average

Question #2 Report Error

Average of 16 numbers 25. If 4 numbers average 30, average of remaining 12?

A. 22

B. 23.33

C. 24

D. 25

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Correct Answer: Option B

Explanation:
Sum16=400. Sum4=120. Remaining=280/12≈23.33.

This question belongs to: Maths Average

Question #3 Report Error

Average of 12 numbers 1220. If average of 8 is 1215, average of remaining 4?

A. 1225

B. 1232

C. 1228

D. 1230

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Correct Answer: Option D

Explanation:
Sum12=14640. Sum8=9720. Remaining=4920. Average=1230.

This question belongs to: Maths Average

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