The centre of mass of a two-particle system lies on the line joining them, closer to MCQ with Answer and Explanation

The centre of mass of a two-particle system lies on the line joining them, closer to
A. Midpoint always
B. Depends on velocity
C. Lighter particle
D. Heavier particle
Answer: Option D
Solution (By JKExamLibrary)
r_cm = (m1 r1 + m2 r2)/(m1+m2). Closer to heavier mass.

This question belongs to: Science Physics

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Question #1 Report Error
The dimensions of surface tension are the same as that of:
A. Viscosity
B. Spring constant
C. Pressure
D. Force

Correct Answer: Option B


Explanation:
Surface tension is defined as Force per unit length (F/L). Dimensional formula: [MLT⁻²] / [L] = [MT⁻²]. A spring constant (k) is defined by Hooke's Law as Force per unit extension (F/x), which also has dimensions [MLT⁻²] / [L] = [MT⁻²]. Thus, both share the same dimensional formula.

This question belongs to: Science Physics
Question #2 Report Error
Body moving with constant velocity has:
A. Constant acceleration
B. Variable acceleration
C. Zero acceleration
D. Increasing acceleration

Correct Answer: Option C


Explanation:
Constant velocity ⇒ no change in speed or direction ⇒ acceleration = dv/dt = 0. Newton's first law: zero net force for constant velocity. Memory tip: 'Constant v ⇒ a = 0; changing v ⇒ a ≠ 0'. Basic kinematics concept frequently tested to verify acceleration-velocity relationship understanding.

This question belongs to: Science Physics
Question #3 Report Error
The gravitational force between two objects of masses 2 kg and 3 kg separated by 2 m (G = 6.67×10⁻¹¹) is
A. 2×10⁻¹⁰ N
B. 6.67×10⁻¹¹ N
C. 1.0005×10⁻¹⁰ N
D. 1×10⁻¹⁰ N

Correct Answer: Option C


Explanation:
F = G m1 m2 / r² = 6.67×10⁻¹¹ × 6 / 4 = 6.67×10⁻¹¹ × 1.5 = 1.0005×10⁻¹⁰ N.

This question belongs to: Science Physics