The commercial unit of electrical energy is MCQ with Answer and Explanation
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Question #1
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Which of the following is an SI derived unit named after a scientist?
Question #2
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A machine gun fires 60 bullets per minute, each of mass 10 g with velocity 600 m/s. The power developed by the gun is:
Correct Answer: Option D
Explanation:
Power = work done per unit time = kinetic energy imparted per second. KE per bullet = ½mv² = ½×0.01×(600)² = 1800 J. Bullets per second = 60/60 = 1. Thus power = 1800 J/s = 1800 W. Note: Mass conversion: 10 g = 0.01 kg. This problem combines kinetic energy formula with power definition. Exam tip: Always convert to SI units first (grams to kg, minutes to seconds). Such numerical problems test multi-step calculation skills and unit conversion proficiency essential for competitive examinations.
Power = work done per unit time = kinetic energy imparted per second. KE per bullet = ½mv² = ½×0.01×(600)² = 1800 J. Bullets per second = 60/60 = 1. Thus power = 1800 J/s = 1800 W. Note: Mass conversion: 10 g = 0.01 kg. This problem combines kinetic energy formula with power definition. Exam tip: Always convert to SI units first (grams to kg, minutes to seconds). Such numerical problems test multi-step calculation skills and unit conversion proficiency essential for competitive examinations.
Question #3
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Alpha particles are fundamentally equivalent to:
Correct Answer: Option B
Explanation:
An alpha particle consists of two protons and two neutrons tightly bound together. This is completely identical to the nucleus of a helium atom (He²⁺). Alpha particles are positively charged, relatively massive, have low penetrating power, and are emitted by heavy radioactive elements during alpha decay.
An alpha particle consists of two protons and two neutrons tightly bound together. This is completely identical to the nucleus of a helium atom (He²⁺). Alpha particles are positively charged, relatively massive, have low penetrating power, and are emitted by heavy radioactive elements during alpha decay.
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