The difference between CI and SI on a certain sum for 2 years at 6% is Rs. 36. The sum is: MCQ with Answer and Explanation

The difference between CI and SI on a certain sum for 2 years at 6% is Rs. 36. The sum is:
A. Rs. 8000
B. Rs. 11000
C. Rs. 9000
D. Rs. 10000
Answer: Option D
Solution (By JKExamLibrary)
D = P × (0.06)² = P × 0.0036 = 36 ⇒ P = 10000.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
The compound interest on a certain sum of money for 2 years at 8% per annum is Rs. 416. What would be the simple interest on the same sum at the same rate for the same time?
A. Rs. 380
B. Rs. 410
C. Rs. 412
D. Rs. 400

Correct Answer: Option D


Explanation:
Effective rate of compound interest for 2 years at 8% = 8 + 8 + (88)/100 = 16.64%. Simple interest rate = 8 * 2 = 16%. Given 16.64% of sum = 416 => 1% of sum = 25. Simple Interest = 16% of sum = 16 * 25 = Rs. 400.

This question belongs to: Maths Compound Interest
Question #2 Report Error
The difference between the simple interest and compound interest on a certain sum of money for 2 years at 12% per annum is Rs. 72. Find the sum.
A. Rs. 5000
B. Rs. 5500
C. Rs. 6000
D. Rs. 4500

Correct Answer: Option A


Explanation:
Difference for 2 years = P * (R/100)^2 => 72 = P * (12/100)^2 => 72 = P * (144 / 10000) => P = (72 * 10000) / 144 = 5000.

This question belongs to: Maths Compound Interest
Question #3 Report Error
The difference between compound interest (compounded annually) and simple interest on a certain sum of money for 3 years at 5% per annum is Rs. 122. Find the sum.
A. Rs. 15000
B. Rs. 16000
C. Rs. 17000
D. Rs. 18000

Correct Answer: Option B


Explanation:
Difference for 3 years = P * (R/100)^2 * (3 + R/100) => 122 = P * (5/100)^2 * (3 + 5/100) => 122 = P * (1/400) * (3.05) => 122 = P * (3.05 / 400) => P = (122 * 400) / 3.05 = 48800 / 3.05 = Rs. 16000.

This question belongs to: Maths Compound Interest