The dimensional formula of coefficient of viscosity is
A. [ML⁻¹T⁻¹]
B. [MLT⁻¹]
C. [ML⁻²T]
D. [M⁰LT⁻¹]
Answer: Option A
Solution (By JKExamLibrary)
Viscosity η = Force/(Area × velocity gradient). Force [MLT⁻²], area [L²], velocity gradient [T⁻¹]. So η = [MLT⁻²]/([L²][T⁻¹]) = [ML⁻¹T⁻¹]. Often asked.
Explanation:
Voltmeter connected parallel, should draw minimum current, so ideally infinite resistance. Ammeter connected series, ideally zero resistance. Galvanometer moderate. Practical voltmeter has high but finite resistance.
Assertion (A): When ice floats in water, its approximately 1/10th volume remains outside the water. Reason (R): The density of ice is approximately 10% less than the density of water.
A.A is false but R is true.
B.Both A and R are true but R is NOT the correct explanation of A.
C.A is true but R is false.
D.Both A and R are true and R is the correct explanation of A.
Explanation:
The density of ice is about 900 kg/m³ (0.9 g/cm³), while pure water is 1000 kg/m³ (1.0 g/cm³). According to the principle of floatation, the fraction of volume submerged is the ratio of densities: ρ_ice / ρ_water = 0.9. This means 90% is submerged, leaving exactly 10% (1/10th) exposed above the surface. Reason R explains Assertion A.
Explanation:
Coefficient of performance (COP) for refrigerator: COP = Q₂ / W, where Q₂ is heat extracted from cold reservoir, W is work input. By energy conservation, Q₁ = Q₂ + W (heat rejected to hot reservoir). COP > 1 typically. Option A is inverse; C and D relate to heat engine efficiency. Memory aid: 'Refrigerator COP = desired output (cooling) / work input'. This thermodynamics definition is frequently tested in competitive exams. Always distinguish refrigerator COP (cooling effect per work) from heat engine efficiency (work output per heat input).
No comments yet. Be the first to start the discussion!