The instrument used to measure the wavelength of light is: MCQ with Answer and Explanation

The instrument used to measure the wavelength of light is:
A. Interferometer
B. Microscope
C. Telescope
D. Spectrometer
Answer: Option D
Solution (By JKExamLibrary)
Spectrometer measures wavelengths of light using diffraction gratings or prisms to disperse light and angular measurements. Interferometer (D) can also measure wavelength but spectrometer is the standard instrument for spectral analysis. Microscope and telescope magnify images, not measure wavelength. Memory tip: 'Spectrometer = wavelength measurement via dispersion; used in spectroscopy'. This instrument-application question tests practical physics knowledge, frequently examined in competitive exams. Always associate instruments with their primary function; competitive exams often test context-specific uses.

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Practice More Physics Questions

Question #1
Three resistors of 2Ω, 3Ω, and 6Ω are connected in parallel. The equivalent resistance is:
A. 11Ω
B.
C.
D. 0.5Ω

Correct Answer: Option C


Explanation:
For parallel combination: 1/R_eq = 1/R₁ + 1/R₂ + 1/R₃ = 1/2 + 1/3 + 1/6 = (3+2+1)/6 = 6/6 = 1. Thus R_eq = 1Ω. Note: Equivalent resistance in parallel is always less than the smallest individual resistance (here 2Ω). Memory tip: 'Parallel: reciprocal sum; result < min(R)'. This standard calculation tests parallel resistance formula application, frequently appearing in competitive exams. Always simplify fractions carefully; common denominator method avoids errors. Verify: 1Ω < 2Ω, consistent with parallel behavior.

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The uncertainty principle was proposed by
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B. Heisenberg
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Correct Answer: Option B


Explanation:
Heisenberg's uncertainty principle: Δx·Δp ≥ h/4π.

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The process of evaporation causes
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Correct Answer: Option C


Explanation:
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