A ball is dropped from a height 'h' and simultaneously another ball is thrown horizontally from the same height. Which ball will hit the ground first? (Neglect air resistance)
Explanation:
Vertical and horizontal motions are completely independent. Both balls have zero initial downward (vertical) velocity and both are subject to the same downward acceleration due to gravity (g). Since the vertical height (h) is the same, using h = ut + ½gt², time t = √(2h/g) applies equally to both. Thus, they hit the ground simultaneously.
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