The phenomenon of persistence of sound due to multiple reflections is called MCQ with Answer and Explanation

The phenomenon of persistence of sound due to multiple reflections is called
A. Echo
B. Reverberation
C. Resonance
D. Doppler effect
Answer: Option B
Solution (By JKExamLibrary)
Reverberation is prolongation of sound due to reflections blending. Echo is distinct repetition.

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Practice More Physics Questions

Question #1
Enrico Fermi is most famously recognized for his pioneering achievement in building the world's first:
A. X-ray machine
B. Particle Accelerator (Cyclotron)
C. Atomic Bomb
D. Nuclear Reactor

Correct Answer: Option D


Explanation:
Enrico Fermi led the team that constructed 'Chicago Pile-1', which achieved the world's first artificial, self-sustaining nuclear chain reaction on December 2, 1942. This was the first nuclear reactor. While he worked on the Manhattan Project (atomic bomb), his crowning individual distinction is creating the first controlled reactor.

This question belongs to: Science Physics
Question #2
What is the relationship between the time period (T) and frequency (f) of a wave?
A. T = f²
B. T = f
C. T = 1 / f
D. T = v × f

Correct Answer: Option C


Explanation:
Frequency (f) is defined as the number of complete oscillations or cycles a wave makes in one second (measured in Hertz). The Time period (T) is the time taken to complete one full oscillation (measured in seconds). They are inversely related: T = 1/f. If a wave has a frequency of 50 Hz, its period is 1/50 seconds.

This question belongs to: Science Physics
Question #3
An athlete runs 200 m in 20 seconds, then returns 100 m back in 10 seconds. The average speed for entire motion is
A. 6.67 m/s
B. 15 m/s
C. 10 m/s
D. 7.5 m/s

Correct Answer: Option A


Explanation:
Total distance = 200 m (forward) + 100 m (back) = 300 m. Total time = 20 s + 10 s = 30 s. Average speed = total distance / total time = 300/30 = 10 m/s. Average velocity would be displacement (200-100=100 m) / 30 s = 3.33 m/s. But average speed is 10 m/s. Wait, 300/30 = 10. But that's option A 10 m/s. I need to check: Did I compute right? 200 m forward, then returns 100 m back, so total path length = 300 m. Time total = 30 s. Average speed = 10 m/s. Option A is 10 m/s, B is 6.67. That gives A. But to test concept, many confuse with velocity. I'll set correct answer A. But I'll adjust to make distinction: Maybe distance first 200 m at 10 m/s, return 100 m at 5 m/s? Already given times. So correct answer A. It's moderate. I'll keep.

This question belongs to: Science Physics