The population of a city increases at the rate of 5% annually. If the present population is 185220, what was its population 3 years ago? MCQ with Answer and Explanation

The population of a city increases at the rate of 5% annually. If the present population is 185220, what was its population 3 years ago?
A. 170000
B. 150000
C. 160000
D. 180000
Answer: Option C
Solution (By JKExamLibrary)
Population 3 years ago = 185220 / (1 + 5/100)^3 = 185220 / (21/20)^3 = 185220 * 8000 / 9261 = 20 * 8000 = 160000.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
The simple interest on a sum for 2 years at 7% is Rs. 280. The compound interest on the same sum for 2 years at 7% is:
A. Rs. 300.00
B. Rs. 294.00
C. Rs. 297.20
D. Rs. 289.80

Correct Answer: Option D


Explanation:
P = 28000/(7×2) = 2000. CI = 2000[(1.07)² − 1] = 2000 × 0.1449 = 289.80.

This question belongs to: Maths Compound Interest
Question #2 Report Error
A sum of money placed at compound interest triples itself in 5 years. In how many years will it become 9 times of itself?
A. 15 years
B. 12 years
C. 10 years
D. 8 years

Correct Answer: Option C


Explanation:
The sum becomes 3^1 times in 5 years. It will become 9 (3^2) times in 2 * 5 = 10 years.

This question belongs to: Maths Compound Interest
Question #3 Report Error
What is the compound interest on Rs. 16000 for 1.5 years at 10% per annum, compounded half-yearly?
A. Rs. 2522
B. Rs. 2520
C. Rs. 2400
D. Rs. 2600

Correct Answer: Option A


Explanation:
Half-yearly rate = 10/2 = 5%. Time = 1.5 years = 3 half-years. Amount = 16000 * (1 + 5/100)^3 = 16000 * (1.05)^3 = 16000 * 1.157625 = Rs. 18522. Compound Interest = 18522 - 16000 = Rs. 2522.

This question belongs to: Maths Compound Interest