The population of a town increases at 10% per annum. If the present population is 20000, what will it be after 2 years? MCQ with Answer and Explanation

The population of a town increases at 10% per annum. If the present population is 20000, what will it be after 2 years?
A. 24600
B. 24400
C. 24000
D. 24200
Answer: Option D
Solution (By JKExamLibrary)
Population = 20000 × (1.1)² = 20000 × 1.21 = 24200.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
The compound interest on a certain sum for 2 years at 4% per annum is Rs. 1632. Find the principal sum.
A. Rs. 22000
B. Rs. 24000
C. Rs. 18000
D. Rs. 20000

Correct Answer: Option D


Explanation:
Effective rate of compound interest for 2 years at 4% = 4 + 4 + (44)/100 = 8.16%. Given 8.16% of P = 1632 => P = 1632 / 0.0816 = Rs. 20000.

This question belongs to: Maths Compound Interest
Question #2 Report Error
Find the compound interest on Rs. 7200 at 5% per annum for 2 years.
A. Rs. 742
B. Rs. 738
C. Rs. 744
D. Rs. 740

Correct Answer: Option B


Explanation:
A = 7200 × (1.05)² = 7200 × 1.1025 = 7938, CI = 7938 − 7200 = Rs. 738.

This question belongs to: Maths Compound Interest
Question #3 Report Error
A sum of money amounts to Rs. 6690 after 3 years and to Rs. 10035 after 6 years on compound interest. Find the sum.
A. Rs. 4660
B. Rs. 4460
C. Rs. 4500
D. Rs. 4000

Correct Answer: Option B


Explanation:
Let the principal be P and expansion factor over 3 years be x. P * x = 6690 and P * x^2 = 10035. Therefore, x = 10035 / 6690 = 1.5. Principal P = 6690 / 1.5 = Rs. 4460.

This question belongs to: Maths Compound Interest