The population of a town increases by 10% per annum. If the present population is 6050, what was it 2 years ago? MCQ with Answer and Explanation

The population of a town increases by 10% per annum. If the present population is 6050, what was it 2 years ago?
A. 6000
B. 5500
C. 5800
D. 5000
Answer: Option D
Solution (By JKExamLibrary)
Population 2 years ago = 6050 / (1.1)² = 6050 / 1.21 = 5000.

This question belongs to: Maths Compound Interest

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Practice More Compound Interest Questions

Question #1 Report Error
A sum of money placed at compound interest becomes double of itself in 5 years. In how many years will it become 128 times of itself?
A. 30 years
B. 45 years
C. 40 years
D. 35 years

Correct Answer: Option D


Explanation:
The sum becomes 2^1 times in 5 years. It will become 128 (2^7) times in 7 * 5 = 35 years.

This question belongs to: Maths Compound Interest
Question #2 Report Error
A sum of money doubles itself at compound interest in 8 years. In how many years will it become 16 times?
A. 24 years
B. 32 years
C. 36 years
D. 28 years

Correct Answer: Option B


Explanation:
2 times in 8 years, 16 = 2⁴, so 8 × 4 = 32 years.

This question belongs to: Maths Compound Interest
Question #3 Report Error
The effective annual rate of interest for 10% per annum compounded quarterly is:
A. 10.50%
B. 10.47%
C. 10.38%
D. 10.25%

Correct Answer: Option C


Explanation:
Quarterly rate 2.5%, (1.025)⁴ = 1.10381289, effective = 10.3813% ≈ 10.38%.

This question belongs to: Maths Compound Interest