The work done by the gravitational force when a body is moved horizontally on Earth's surface is: MCQ with Answer and Explanation

The work done by the gravitational force when a body is moved horizontally on Earth's surface is:
A. Negative
B. Depends on speed
C. Zero
D. Positive
Answer: Option C
Solution (By JKExamLibrary)
Gravitational force acts vertically downward. For horizontal displacement, the angle between force and displacement is 90°, so work W = F·d·cos90° = 0. Gravity does no work for horizontal motion; it only does work for vertical displacement components. Memory aid: 'Work = F d cosθ; θ=90° ⇒ W=0'.

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Practice More Physics Questions

Question #1
The phenomenon of diffraction is evidence for the:
A. Wave nature of light
B. Particle nature of light
C. Dual nature of light
D. Electromagnetic nature of light

Correct Answer: Option A


Explanation:
Diffraction (bending of waves around obstacles) is a characteristic wave phenomenon, explained by Huygens' principle and wave superposition. It demonstrates light's wave nature, as particles would travel in straight lines. Particle nature is shown by photoelectric effect; dual nature combines both. Memory aid: 'Diffraction/interference ⇒ wave nature; photoelectric effect ⇒ particle nature'. This conceptual question tests wave-particle duality fundamentals, frequently examined in competitive exams. Always link specific phenomena to the aspect of light they demonstrate; competitive exams often combine both aspects in advanced questions requiring nuanced understanding.

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Question #2
A body covers 12 m in the 2nd second and 20 m in the 4th second of its motion. Assuming uniform acceleration, what is its initial velocity?
A. 6 m/s
B. 4 m/s
C. 2 m/s
D. 8 m/s

Correct Answer: Option A


Explanation:
The distance covered in the nth second is Sn = u + a/2 * (2n - 1). For n=2: 12 = u + a/2 * (3) => 2u + 3a = 24. For n=4: 20 = u + a/2 * (7) => 2u + 7a = 40. Subtracting equations: 4a = 16 => a = 4 m/s^2. Substitute 'a' back: 2u + 3(4) = 24 => 2u = 12 => u = 6 m/s.

This question belongs to: Science Physics
Question #3
The heating effect of electric current is described by:
A. Joule's law
B. Ohm's law
C. Faraday's law
D. Lenz's law

Correct Answer: Option A


Explanation:
Joule's law states that heat produced H = I²Rt, where I is current, R resistance, t time. This quantifies electrical energy converted to thermal energy in resistors. Ohm's law relates V, I, R; Faraday's and Lenz's laws concern electromagnetic induction. Memory aid: 'Joule heating ∝ I²R'. This definition-based question tests knowledge of fundamental laws in electricity, commonly examined in competitive exams. Applications include electric heaters, fuses, and incandescent bulbs. Always distinguish Joule's law (heating) from power formulas (P=VI=I²R=V²/R).

This question belongs to: Science Physics