Two numbers are in ratio 11:4. Their difference is 116. What is their sum? MCQ with Answer and Explanation
Question
Report Error
Discuss this Question (0)
Practice More Ratio and Proportion Questions
Question #1
Report Error
Ratio of present ages of A and B is 5:4. After 12 years, the ratio becomes 8:5. Present age of A is?
Correct Answer: Option D
Explanation:
Let ages 5k and 4k. Then (5k + 12)/(4k + 12) = 8/5. Solving gives k ≈ 23, age of A = 5*23 = 115.
Let ages 5k and 4k. Then (5k + 12)/(4k + 12) = 8/5. Solving gives k ≈ 23, age of A = 5*23 = 115.
This question belongs to:
Maths
Ratio and Proportion
Question #2
Report Error
If a:b = 2:3 and b:c = 3:10, then a:b:c = ?
Correct Answer: Option C
Explanation:
Combine ratios: a:b = 2:3, b:c = 3:10 ⇒ a:b:c = 2:3:10.
Combine ratios: a:b = 2:3, b:c = 3:10 ⇒ a:b:c = 2:3:10.
This question belongs to:
Maths
Ratio and Proportion
Question #3
Report Error
Two numbers are in ratio 6:4. Their difference is 60. What is their sum?
Correct Answer: Option A
Explanation:
Numbers 6k, 4k. Difference |6-4|k = 60 ⇒ k = 30. Sum = (6+4)k ≈ 350.
Numbers 6k, 4k. Difference |6-4|k = 60 ⇒ k = 30. Sum = (6+4)k ≈ 350.
This question belongs to:
Maths
Ratio and Proportion
No comments yet. Be the first to start the discussion!