Two numbers are in ratio 7:12. Their difference is 101. What is their sum? MCQ with Answer and Explanation

Two numbers are in ratio 7:12. Their difference is 101. What is their sum?
A. 152
B. 304
C. 423
D. 334
Answer: Option B
Solution (By JKExamLibrary)
Numbers 7k, 12k. Difference |7-12|k = 101 ⇒ k = 20. Sum = (7+12)k ≈ 304.

This question belongs to: Maths Ratio and Proportion

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Practice More Ratio and Proportion Questions

Question #1 Report Error
If a:b = 8:10 and b:c = 10:12, then a:b:c = ?
A. 8:11:12
B. 16:20:24
C. 7:10:13
D. 8:10:12

Correct Answer: Option D


Explanation:
Combine ratios: a:b = 8:10, b:c = 10:12 ⇒ a:b:c = 8:10:12.

This question belongs to: Maths Ratio and Proportion
Question #2 Report Error
If a:b = 4:4 and b:c = 4:8, then a:b:c = ?
A. 3:4:9
B. 8:8:16
C. 4:4:8
D. 4:5:8

Correct Answer: Option C


Explanation:
Combine ratios: a:b = 4:4, b:c = 4:8 ⇒ a:b:c = 4:4:8.

This question belongs to: Maths Ratio and Proportion
Question #3 Report Error
If a:b = 3:8 and b:c = 8:10, then a:b:c = ?
A. 3:9:10
B. 3:8:10
C. 2:8:11
D. 6:16:20

Correct Answer: Option B


Explanation:
Combine ratios: a:b = 3:8, b:c = 8:10 ⇒ a:b:c = 3:8:10.

This question belongs to: Maths Ratio and Proportion