Wire stretched to double length (volume constant). New resistance: MCQ with Answer and Explanation

Wire stretched to double length (volume constant). New resistance:
A. R/2
B. R
C. 4R
D. 2R
Answer: Option C
Solution (By JKExamLibrary)
Volume constant: A' = A/2 when L' = 2L. R' = ρ(2L)/(A/2) = 4ρL/A = 4R. Memory tip: 'Stretch wire: R ∝ L² when volume fixed'. Resistance proportionality frequently tested in competitive exams.

This question belongs to: Science Physics

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