A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school.
A delivery coach covers a highway stretch at 40 km/h. If the driver spikes the speed index to 60 km/h, the coach lands at the station terminal 15 minutes early. Find the track sector distance.
Explanation:
Time difference = 15 minutes = 15/60 = 1/4 hours. Let distance be d. d / 40 - d / 60 = 1/4 => (3d - 2d) / 120 = 1/4 => d / 120 = 1/4 => d = 30 km.
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