A body weighs 72 N on the surface of the Earth. What is the gravitational force on it at a height equal to half the radius of the Earth? MCQ with Answer and Explanation

A body weighs 72 N on the surface of the Earth. What is the gravitational force on it at a height equal to half the radius of the Earth?
A. 32 N
B. 28 N
C. 72 N
D. 16 N
Answer: Option A
Solution (By JKExamLibrary)
Weight on surface W = mg = 72 N. Acceleration due to gravity at height h is g' = g [R / (R+h)]². Here h = R/2. So, g' = g [R / (R + R/2)]² = g [1 / (3/2)]² = g (2/3)² = 4g/9. The new weight W' = mg' = m(4g/9) = (4/9)mg = (4/9) × 72 = 32 N.

This question belongs to: Science Physics

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