A can complete a work in 14 days and B in 12 days. If they work together, the work will be completed in: MCQ with Answer and Explanation
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Question #1
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A and B can do a work in 12 days, B and C in 15 days and C and A in 20 days. In how many days can A alone complete the work?
Correct Answer: Option A
Explanation:
Total work = LCM(12, 15, 20) = 60 units. Efficiency of (A+B) = 5, (B+C) = 4, (C+A) = 3. Summing these gives 2*(A+B+C) = 12 => Efficiency of (A+B+C) = 6. Efficiency of A = (A+B+C) - (B+C) = 6 - 4 = 2. Time taken by A alone = 60 / 2 = 30 days.
Total work = LCM(12, 15, 20) = 60 units. Efficiency of (A+B) = 5, (B+C) = 4, (C+A) = 3. Summing these gives 2*(A+B+C) = 12 => Efficiency of (A+B+C) = 6. Efficiency of A = (A+B+C) - (B+C) = 6 - 4 = 2. Time taken by A alone = 60 / 2 = 30 days.
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Maths
Time and Work
Question #2
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15 men can complete a work in 23 days. If 23 men work at the same rate, how many days are required?
Correct Answer: Option B
Explanation:
Total work = 345 man-days. Days = 15.0.
Total work = 345 man-days. Days = 15.0.
This question belongs to:
Maths
Time and Work
Question #3
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If 3 men or 5 women can do a piece of work in 12 days, in how many days will 6 men and 5 women complete the same work?
Correct Answer: Option D
Explanation:
3 Men = 5 Women => 6 Men = 10 Women. 6 men + 5 women = 10 women + 5 women = 15 women. Since 5 women take 12 days, 15 women will take (5 * 12) / 15 = 60 / 15 = 4 days.
3 Men = 5 Women => 6 Men = 10 Women. 6 men + 5 women = 10 women + 5 women = 15 women. Since 5 women take 12 days, 15 women will take (5 * 12) / 15 = 60 / 15 = 4 days.
This question belongs to:
Maths
Time and Work
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