A car covered a distance of 180 km at a uniform speed. If the speed is reduced by 5 km/h, the journey takes 1 hour longer. Find the original speed. MCQ with Answer and Explanation
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Question #1
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A merchant van covers 120 km at 40 km/h, 180 km at 60 km/h and 100 km at 50 km/h. Find the net average speed.
Correct Answer: Option A
Explanation:
Total distance = 120 + 180 + 100 = 400 km. Total time = (120/40) + (180/60) + (100/50) = 3 + 3 + 2 = 8 hours. Average speed = 400 / 8 = 50 km/h.
Total distance = 120 + 180 + 100 = 400 km. Total time = (120/40) + (180/60) + (100/50) = 3 + 3 + 2 = 8 hours. Average speed = 400 / 8 = 50 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A car tracks a total segment of 360 km. If the uniform speed is boosted by 15 km/h, it covers the course in 4 hours flat. Find the original speed.
Correct Answer: Option C
Explanation:
New speed = 360 / 4 = 90 km/h. Since the new speed is 15 km/h faster than original speed, original speed = 90 - 15 = 75 km/h.
New speed = 360 / 4 = 90 km/h. Since the new speed is 15 km/h faster than original speed, original speed = 90 - 15 = 75 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 180 meters long is tracking at a uniform speed of 72 km/h. How many seconds will it take to clear a stationary passenger standing on a platform?
Correct Answer: Option C
Explanation:
Speed of train = 72 * (5/18) = 20 m/s. Time taken to clear the passenger = 180 / 20 = 9 seconds.
Speed of train = 72 * (5/18) = 20 m/s. Time taken to clear the passenger = 180 / 20 = 9 seconds.
This question belongs to:
Maths
Time Speed and Distance
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