A car covers a distance of 240 km in 3 hours 20 minutes. Find its average speed. MCQ with Answer and Explanation
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Question #1
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A car travels a distance of 240 km at a certain speed. If the speed is increased by 10 km/h, it takes 4 hours for the journey. Find the original speed.
Correct Answer: Option A
Explanation:
New speed = 240 / 4 = 60 km/h. Since new speed is original speed + 10 km/h, the original speed = 60 - 10 = 50 km/h.
New speed = 240 / 4 = 60 km/h. Since new speed is original speed + 10 km/h, the original speed = 60 - 10 = 50 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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An express train covers a distance of 450 km in 5 hours. If a slower local train runs at half the speed of the express train, how much time will the local train take to cover 360 km?
Correct Answer: Option D
Explanation:
Speed of express train = 450 / 5 = 90 km/h. Speed of local train = 90 / 2 = 45 km/h. Time taken by local train = 360 / 45 = 8 hours.
Speed of express train = 450 / 5 = 90 km/h. Speed of local train = 90 / 2 = 45 km/h. Time taken by local train = 360 / 45 = 8 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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The speed tracking profile of an express train is exactly 25% higher than a commercial car. Both take off from terminal A together and reach terminal B, 200 km away, at the same instant. On the corridor route, the train logs a total stall of 20 minutes at checkpoints. Find the car speed.
Correct Answer: Option D
Explanation:
Let car speed be c, then train tracking speed is 1.25c. Time difference parameter = 200/c - 200/(1.25c) = 20/60 hours = 1/3 hours. 200/c * (1 - 1/1.25) = 1/3 => 200/c * (0.25/1.25) = 1/3 => 200/c * (1/5) = 1/3 => 40/c = 1/3 => c = 120 km/h.
Let car speed be c, then train tracking speed is 1.25c. Time difference parameter = 200/c - 200/(1.25c) = 20/60 hours = 1/3 hours. 200/c * (1 - 1/1.25) = 1/3 => 200/c * (0.25/1.25) = 1/3 => 200/c * (1/5) = 1/3 => 40/c = 1/3 => c = 120 km/h.
This question belongs to:
Maths
Time Speed and Distance
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