A car travels a distance of 300 km at a certain speed. If the speed is increased by 10 km/h, it takes 5 hours for the journey. Find the original speed. MCQ with Answer and Explanation
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Question #1
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A passenger train 100 meters long clears a line worker tracking on the ballast track in 5 seconds flat when both move along the identical direction. If the line worker walks at 8 km/h, find the train speed.
Correct Answer: Option A
Explanation:
Relative tracking speed = 100 / 5 = 20 m/s = 20 * (18/5) = 72 km/h. In identical directions, Relative Speed = Speed of train - Speed of worker => 72 = Speed of train - 8 => Speed of train = 80 km/h.
Relative tracking speed = 100 / 5 = 20 m/s = 20 * (18/5) = 72 km/h. In identical directions, Relative Speed = Speed of train - Speed of worker => 72 = Speed of train - 8 => Speed of train = 80 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A courier covers 40 km of his shift route at 20 km/h and the remaining 60 km at 30 km/h. Find his average speed across the whole shift.
Correct Answer: Option C
Explanation:
Total distance = 40 + 60 = 100 km. Time for first sector = 40 / 20 = 2 hours. Time for second sector = 60 / 30 = 2 hours. Total time = 4 hours. Average speed = 100 / 4 = 25 km/h.
Total distance = 40 + 60 = 100 km. Time for first sector = 40 / 20 = 2 hours. Time for second sector = 60 / 30 = 2 hours. Total time = 4 hours. Average speed = 100 / 4 = 25 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A van moves at 45 km/h for 2 hours and then tracks at 55 km/h for the next 3 hours. Find the net average speed for the total route.
Correct Answer: Option B
Explanation:
Distance 1 = 45 * 2 = 90 km. Distance 2 = 55 * 3 = 165 km. Total distance = 255 km. Total time = 5 hours. Average speed = 255 / 5 = 51 km/h.
Distance 1 = 45 * 2 = 90 km. Distance 2 = 55 * 3 = 165 km. Total distance = 255 km. Total time = 5 hours. Average speed = 255 / 5 = 51 km/h.
This question belongs to:
Maths
Time Speed and Distance
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