A commuter sets a pace of 4 km/h and reaches his branch office 10 minutes late. If he increases his pace to 6 km/h, he still reaches 2 minutes late. Find the distance. MCQ with Answer and Explanation
Question
Report Error
Discuss this Question (0)
Practice More Time Speed and Distance Questions
Question #1
Report Error
The speed of a boat in still water is 14 km/h and the speed of the current is 4 km/h. How much distance can the boat cover upstream in 2 hours?
Correct Answer: Option C
Explanation:
Upstream speed = 14 - 4 = 10 km/h. Distance covered in 2 hours = 10 * 2 = 20 km.
Upstream speed = 14 - 4 = 10 km/h. Distance covered in 2 hours = 10 * 2 = 20 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
Report Error
A car covers a distance of 180 km at 45 km/h and another 180 km at 60 km/h. Find the total time spent during the journey.
Correct Answer: Option D
Explanation:
Time for first part = 180 / 45 = 4 hours. Time for second part = 180 / 60 = 3 hours. Total time taken = 4 + 3 = 7 hours.
Time for first part = 180 / 45 = 4 hours. Time for second part = 180 / 60 = 3 hours. Total time taken = 4 + 3 = 7 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #3
Report Error
A car travels a distance of 240 km at a uniform speed. If the speed is reduced by 10 km/h, it takes 2 hours longer. Find the original speed.
Correct Answer: Option A
Explanation:
Let original speed be s. 240 / (s - 10) - 240 / s = 2 => 120 / (s - 10) - 120 / s = 1 => 1200 = s(s - 10). Solving s^2 - 10s - 1200 = 0 gives (s - 40)(s + 30) = 0. Since speed is positive, s = 40 km/h.
Let original speed be s. 240 / (s - 10) - 240 / s = 2 => 120 / (s - 10) - 120 / s = 1 => 1200 = s(s - 10). Solving s^2 - 10s - 1200 = 0 gives (s - 40)(s + 30) = 0. Since speed is positive, s = 40 km/h.
This question belongs to:
Maths
Time Speed and Distance
No comments yet. Be the first to start the discussion!