A dispatch rider travels between two depots at a speed of 50 km/h and arrives on schedule. If he travels at 40 km/h, he is late by 45 minutes. Find the distance between the two depots. MCQ with Answer and Explanation
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Question #1
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A boatman rows 16 km downstream in 2 hours and covers the same distance upstream in 4 hours. Find the speed of the boat in still water.
Correct Answer: Option B
Explanation:
Downstream speed = 16 / 2 = 8 km/h. Upstream speed = 16 / 4 = 4 km/h. Speed in still water = (8 + 4) / 2 = 6 km/h.
Downstream speed = 16 / 2 = 8 km/h. Upstream speed = 16 / 4 = 4 km/h. Speed in still water = (8 + 4) / 2 = 6 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A person travels a distance of 200 km at an average speed of 50 km/h and returns at a speed of 40 km/h. Find the average speed for the round trip.
Correct Answer: Option A
Explanation:
Average Speed = 2xy / (x + y) = (2 * 50 * 40) / (50 + 40) = 4000 / 90 = 44.44 km/h.
Average Speed = 2xy / (x + y) = (2 * 50 * 40) / (50 + 40) = 4000 / 90 = 44.44 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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If a man walks at 14 km/h instead of 10 km/h, he would have walked 20 km more. What is the actual distance traveled by him?
Correct Answer: Option A
Explanation:
Let the time taken be t hours. Distance difference = 14t - 10t = 4t = 20 km => t = 5 hours. Actual distance = 10 * 5 = 50 km.
Let the time taken be t hours. Distance difference = 14t - 10t = 4t = 20 km => t = 5 hours. Actual distance = 10 * 5 = 50 km.
This question belongs to:
Maths
Time Speed and Distance
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