A field clerk walking at 5 km/h handles a regular sector. If he steps up to run at 10 km/h, he takes 24 minutes less across the course stretch. Find the absolute distance profile. MCQ with Answer and Explanation
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Question #1
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A car maps a course distance of 240 km at an average speed of 60 km/h and handles the return trip at 40 km/h. Find the combined average speed.
Correct Answer: Option A
Explanation:
Average Speed = 2xy / (x + y) = (2 * 60 * 40) / (60 + 40) = 4800 / 100 = 48 km/h.
Average Speed = 2xy / (x + y) = (2 * 60 * 40) / (60 + 40) = 4800 / 100 = 48 km/h.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A runner tracks a circular field of circumference 600 meters. If his speed is 14.4 km/h, how many rounds can he complete in 15 minutes?
Correct Answer: Option A
Explanation:
Speed = 14.4 km/h = 14.4 * (5/18) = 4 m/s. Time = 15 minutes = 900 seconds. Total distance wrapped = 4 * 900 = 3600 meters. Number of rounds completed = 3600 / 600 = 6 rounds.
Speed = 14.4 km/h = 14.4 * (5/18) = 4 m/s. Time = 15 minutes = 900 seconds. Total distance wrapped = 4 * 900 = 3600 meters. Number of rounds completed = 3600 / 600 = 6 rounds.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A train 150 meters long is running at a speed of 90 km/h. How long will it take to cross a platform 200 meters long?
Correct Answer: Option D
Explanation:
Speed of train = 90 * (5/18) = 25 m/s. Total distance = 150 + 200 = 350 meters. Time taken = 350 / 25 = 14 seconds.
Speed of train = 90 * (5/18) = 25 m/s. Total distance = 150 + 200 = 350 meters. Time taken = 350 / 25 = 14 seconds.
This question belongs to:
Maths
Time Speed and Distance
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