A hound pursues a fox that is initially 150 meters ahead. The fox flies at 30 km/h and the hound targets at 36 km/h. Find the total distance the fox runs before capture. MCQ with Answer and Explanation

A hound pursues a fox that is initially 150 meters ahead. The fox flies at 30 km/h and the hound targets at 36 km/h. Find the total distance the fox runs before capture.
A. 800 meters
B. 750 meters
C. 700 meters
D. 850 meters
Answer: Option B
Solution (By JKExamLibrary)
Relative speed = 36 - 30 = 6 km/h = 5/3 m/s. Time required for capture = 150 / (5/3) = 90 seconds. Distance run by fox = Speed * Time = [30 * (5/18)] * 90 = (25/3) * 90 = 750 meters.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A train passes a standing man in 6 seconds and a 210-meter long platform in 16 seconds. Find the speed of the train.
A. 80 km/h
B. 54 km/h
C. 75.6 km/h
D. 72 km/h

Correct Answer: Option C


Explanation:
Let length of train be L. Speed = L/6. Also, Speed = (L + 210)/16. Equating them: L/6 = (L+210)/16 => 16L = 6L + 1260 => 10L = 1260 => L = 126 meters. Speed = 126 / 6 = 21 m/s. Speed in km/h = 21 * (18/5) = 378 / 5 = 75.6 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A private sedan tracks a sector path length of 360 km in 4 hours 30 minutes. Find its mean average speed index.
A. 80 km/h
B. 85 km/h
C. 90 km/h
D. 75 km/h

Correct Answer: Option A


Explanation:
Time = 4.5 hours. Speed index = Sector Distance / Time = 360 / 4.5 = 80 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
The speed index tracking profile of an express locomotive is exactly 20% higher than a commercial car. Both take off from terminal M together and reach terminal N, 120 km away, at the same instant. On the corridor route, the train logs a total stall of 10 minutes at intermediate stations. Find the car speed.
A. 140 km/h
B. 120 km/h
C. 100 km/h
D. 150 km/h

Correct Answer: Option B


Explanation:
Let car speed be c, then train tracking speed is 1.2c. Time difference parameter = 120/c - 120/(1.2c) = 10/60 hours = 1/6 hours. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.

This question belongs to: Maths Time Speed and Distance